Since there can be <-ℓ, ℓ> orientations and since the orbital kind f has ℓ = 3, us should have 7 possible orientations with 2 spins, therefore $7 imes 2 = 14$, for this reason I assumed the correct answer was D (14).

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However, I obtained it wrong and the correct answer is marked as C (2). Is that an error in the test, or am I absent something?

You"re correct that there are seven feasible spatial orientations for an f-type orbital, and also hence seven possible orbitals in one f-type sub-shell. However, the concern specifically asks for the maximum variety of electrons in one together orbital, and

*any*single atomic orbital, regardless of the sub-shell kind specified by $l$, can only host two electrons. This is by virtue of the Pauli exclusion principle. Fourteen would certainly be the maximum number of electrons throughout an entire f-type sub-shell, but the question only asks about one orbital.

The concern specifically ask that no.of electron an orbit of f subshell deserve to hold.... As we recognize that f subshell contain 7 orbital and each orbital have the right to hold best 2 electons so correct answer would be 2..we can simply understand this by taking the genuine life instance imagine that there is house named f which consists of 7 rooms so similarly in this situation house is a subshell and each room is an orbital... Say thanks to you,

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